SOLUTION: Solve the following quadratic equation by factoring (find zeroes) 2x^2-2x-4=0

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Question 1034331: Solve the following quadratic equation by factoring (find zeroes)

2x^2-2x-4=0

Found 2 solutions by Boreal, solver91311:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2-2x-4=0
2(x^2-x-2)=0
2*(x-2)(x+1)=0
This works when x=2 or x= -1
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2x%5E2-2x-4%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




First take out the common integer factor, 2



We are now looking for two binomial factors that have the following characteristics:

1. The product of the constant terms is negative 2.

2. The sum of the constant terms is negative 1.

Since the product is negative, the two constant terms must be of opposite sign. The only two integers that have a product of 2 are 2 and 1, so we know that we are looking for either 2 times -1 or -2 times 1.

Since 2 plus -1 is 1, we can discard this choice because we are looking for a sum of -1. -2 plus 1 is -1, so the two integers must be -2 and 1.

That makes the two factors and

Putting it all back together we get:



Now you have 3 factors whose product is zero. That means one of the factors must be zero. We can eliminate 2 because 2 is not and never will be zero. That leaves and , either of which could be zero given an appropriate value for .

If then

If then

Check:



Checks.



Checks.

John

My calculator said it, I believe it, that settles it