SOLUTION: The expression (2^4)(2^5)(2^-5)/sqrt(4^3)(2^4)(2^-5) equals 2^n where n is? By the way: The sqrt is only on the 4^3.

Algebra ->  Equations -> SOLUTION: The expression (2^4)(2^5)(2^-5)/sqrt(4^3)(2^4)(2^-5) equals 2^n where n is? By the way: The sqrt is only on the 4^3.      Log On


   



Question 1032261: The expression (2^4)(2^5)(2^-5)/sqrt(4^3)(2^4)(2^-5) equals 2^n where n is?

By the way: The sqrt is only on the 4^3.

Found 2 solutions by addingup, MathTherapy:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
Below is what I understood the problem is. If you solve it (use your calculator) you get 1. I'm not sure where you're getting 2^n.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The expression (2^4)(2^5)(2^-5)/sqrt(4^3)(2^4)(2^-5) equals 2^n where n is?

By the way: The sqrt is only on the 4^3.
If , then:
2%5E5%2Fsqrt%284%5E3%29+=+2%5En -----> 2%5E5%2Fsqrt%28%282%5E2%29%5E3%29+=+2%5En ------> 2%5E5%2Fsqrt%282%5E6%29+=+2%5En -------> 2%5E5%2F2%5E3+=+2%5En -------> 2%5E%285+-+3%29+=+2%5En ---------> 2%5E2+=+2%5En ---------> highlight_green%282+=+n%29