SOLUTION: A cashier's drawer has some $5 bills, some $10 bills, and some $20 bills. There are 15 bills worth a total of $185. How many $5 bills, $10 bills, and $20 bills are there?
Algebra ->
Equations
-> SOLUTION: A cashier's drawer has some $5 bills, some $10 bills, and some $20 bills. There are 15 bills worth a total of $185. How many $5 bills, $10 bills, and $20 bills are there?
Log On
Question 103199This question is from textbook Prentice Hall
: A cashier's drawer has some $5 bills, some $10 bills, and some $20 bills. There are 15 bills worth a total of $185. How many $5 bills, $10 bills, and $20 bills are there? This question is from textbook Prentice Hall
You can put this solution on YOUR website! x+y+z=15 number of bills
5x+10y+20z=185 amount in the drawer.
3 unknowns & only 2 equations needs a table
x=====y=====z====value
1=====1=====13===5+10+260=275 too much!
1=====2=====12===5+20+240=265 too much
1=====5=====9====5+50+180=235 too much
1=====10====4====5+100+80=185 looking good for an answer.
proof
1+10+4=15 bills.
1*5+10*10+4*20=5+100+80=185 value.
(