SOLUTION: Hi, I'm having trouble solving and figuring out what to do with this problem: x^2 - 5x - 24 _< (greater than or equal to) 0 Thank you.

Algebra ->  Equations -> SOLUTION: Hi, I'm having trouble solving and figuring out what to do with this problem: x^2 - 5x - 24 _< (greater than or equal to) 0 Thank you.      Log On


   

Question 1027173: Hi, I'm having trouble solving and figuring out what to do with this problem:
x^2 - 5x - 24 _< (greater than or equal to) 0
Thank you.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Find the critical values of x. They will be the ZEROS of the equation. These critical values cut the x-axis number line into three intervals. Pick any value in each interval and test in the INEQUALITY. Either the statement is true or it is false for that interval.

Your critical values are %285%2B-+sqrt%2825%2B4%2A24%29%29%2F2
%285%2B-+sqrt%28121%29%29%2F2
%285%2B-+11%29%2F2
The critical x values, -3 AND 8.

Maybe the two-D overhead parabola view will help too:
graph%28300%2C300%2C-6%2C10%2C-7%2C7%2Cx%5E2-5x-24%29


Solution is -3%3C=x%3C=8.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Hi, I'm having trouble solving and figuring out what to do with this problem:
x^2 - 5x - 24 _< (greater than or equal to) 0
Thank you.
If it's: x%5E2+-+5x+-+24+%3E=+0, then highlight_green%28matrix%281%2C3%2C+x+%3C=+-+3%2C+or%2C+x+%3E=+8%29%29