SOLUTION: What would be the solution to the following system of equations: 2x + y - 3z = 11 -x + 2y + 4z = -3 x - 5y + 2z = -18 A.) (-1, 1, -4) B.) (1, 3, -2) C.) (3, 8, 1) D.

2x +  y - 3z =  11
-x + 2y + 4z =  -3
 x - 5y + 2z = -18

Add the second and third equations 
to eliminate the x:

That will give you an equation with
only y and z in it

Then multiply the second original equation

-x + 2y + 4z =  -3
 
by 2 and add it the the first original equation

2x +  y - 3z =  11

and you will get another equation with
only y and z in it.  

[You will then be able to divide it through by 5.]

That will give you a system of 2 equations
equations in 2 unknowns, y and z.

Then you can solve that system of equations
and find y and z.  

Then finally you will substitute those values
for y and z into any one of the original three
equations and solve for x

If you have trouble, show what you've done in
the thank-you note form below and I'll get
back to you by email.

Edwin