SOLUTION: At noon a train leaves Washington, D.C., headed for Charleston, South Carolina, a distance of 500 mi. The train travels at a speed of 44 mph. At 1 P.M. a second train leaves Charle

Algebra ->  Equations -> SOLUTION: At noon a train leaves Washington, D.C., headed for Charleston, South Carolina, a distance of 500 mi. The train travels at a speed of 44 mph. At 1 P.M. a second train leaves Charle      Log On


   



Question 1024860: At noon a train leaves Washington, D.C., headed for Charleston, South Carolina, a distance of 500 mi. The train travels at a speed of 44 mph. At 1 P.M. a second train leaves Charleston headed for Washington, D.C., traveling at 32 mph. How long after the train leaves Charleston will the two trains pass each other?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In 1 hour ( noon to 1 PM ), how far does the
1st train get?
+d%5B1%5D+=+44%2A1+
+d%5B1%5D+=+44+ mi
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Start a stopwatch when the 2nd train leaves Charleston
Let +t+ = time on stopwatch in hours when
the trains pass eachother
Let +d+ = distance in miles that the 2nd train
travels until they pass eachother
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Equation for the 1st train:
(1) +500+-+44+-+d+=+44t+
Equation for the 2nd train:
(2) +d+=+32t+
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Sustitute (2) into (1)
(1) +500+-+44+-32t+=+44t+
(1) +456+-+32t+=+44t+
(1) +76t+=+456+
(1) +t+=+6+
6 hours after the train leaves Charleston
the two trains pass each other
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check answer:
(2) +d+=+32t+
(2) +d+=+32%2A6+
(2) +d+=+192+
and
(1) +500+-+44+-+d+=+44t+
(1) +500+-+44+-+d+=+44%2A6
(1) +500+-+44+-+d+=+264
(1) +d+=+500+-+44+-+264+
(1) +d+=+500+-+308+
(1) +d+=+192+
OK
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Note that in the 6 hrs, train 1 travels
+500+-+44+-+192+=+264+ mi
and train 2 travels +192+ mi
+264+%2B+192+=+456+
and +456+%2B+44+=+500+
total distance traveled by both