SOLUTION: find the derivative of h(x)=1+e^x÷1-e^x

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Question 1023940: find the derivative of h(x)=1+e^x÷1-e^x
Answer by fractalier(6550) About Me  (Show Source):
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Using the quotient rule we get
h(x) = (1+e^x) ÷ (1-e^x)
h'(x) = (e^x(1-e^x) - (-e^x)(1+e^x)) / (1 - e^x)^2
h'(x) = ((e^x - e^2x) + (e^x + e^2x)) / (1 - e^x)^2
h'(x) = 2e^x / (1 - e^x)^2