SOLUTION: Solve: 7e^3x + 5 = 40 * round to the nearest thousandth * only algebraic solution will be accepted

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Question 1022318: Solve: 7e^3x + 5 = 40
* round to the nearest thousandth
* only algebraic solution will be accepted
Found 3 solutions by Alan3354, MathLover1, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve: 7e^3x + 5 = 40
---
7e^3x = 35
e^3x = 5
x = 5/e^3
x =~ 0.249

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
7e%5E%283x%29+%2B+5+=+40
7e%5E%283x%29+=+40-5
7e%5E%283x%29+=+35
e%5E%283x%29+=+35%2F7
e%5E%283x%29+=+5
log%28%28e%5E%283x%29%29%29+=+log%28%285%29%29
%283x%29log%28%28e%29%29+=+log%28%285%29%29........since log%28%28e%29%29=1
3x+=+log%28%285%29%29
x+=+log%28%285%29%29%2F3
x+=+0.69897%2F3
x+=+0.23299
x+=+0.233

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Solve: 7e^3x + 5 = 40
* round to the nearest thousandth
* only algebraic solution will be accepted
7e%5E%283x%29+%2B+5+=+40

7e%5E%283x%29+=+40+-+5

7e%5E%283x%29+=+35

e%5E%283x%29+=+35%2F7

e%5E%283x%29+=+5

ln 5 = 3x

x+=+%28ln+%285%29%29%2F3, or highlight_green%280.536%29