SOLUTION: write the equation of a line in slope intercept form that crosses -4,-2 and is parallel to the equation 5x-4y=-12 please

Algebra ->  Equations -> SOLUTION: write the equation of a line in slope intercept form that crosses -4,-2 and is parallel to the equation 5x-4y=-12 please      Log On


   

Question 1021172: write the equation of a line in slope intercept form that crosses -4,-2 and is parallel to the equation 5x-4y=-12 please
Found 2 solutions by Fombitz, macston:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel lines have the same left hand side, different right hand side.
5x-4y=D
Use the point to solve for D.
5%28-4%29-4%28-2%29=D
D=-20%2B8
D=-12
.
.
.
.
.
Since the right hand sides are the same, the line already goes through (-4,-2) so there doesn't exist a parallel line that goes through the same point.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
5x-4y=-12
5x+12=4y
(5/4)x+3=y
.
y=(5/4)x+3 . The parallel line will have slope (5/4)
.
Slope intercept form:
y=(5/4)x+b . Use given point to find b.
y=-2; x=-4
-2=(5/4)(-4)+b
-2=-5+b
3=b
.
y=mx+b
y=(5/4)x+3 . This is the same as the original equation
.
ANSWER: The original line goes through the given point