SOLUTION: cost of producing x cars per week is C(x)=1000+400x-0.1x^2 what is the marginal cost at x=300?

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Question 1021070: cost of producing x cars per week is C(x)=1000+400x-0.1x^2
what is the marginal cost at x=300?
Found 3 solutions by MathLover1, robertb, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
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C%28x%29=1000%2B400x-0.1x%5E2
the marginal cost at x=300 will be:
C%28300%29=1000%2B400%2A300-0.1%2A300%5E2
C%28300%29=1000%2B120000-0.1%2A90000
C%28300%29=1000%2B120000-9000
C%28300%29=112000

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The marginal cost function is simply the derivative of the total cost function.
==> MC(x) = 400 - 0.2x
==> MC(300) = 400 - 0.2*300 = 340.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!
cost of producing x cars per week is C(x)=1000+400x-0.1x^2
what is the marginal cost at x=300?
Marginal cost: 1st derivative of function, so C%28x%29+=+1000+%2B+400x+-+0.1x%5E2 becomes: M%28x%29+=+400+-+.2x

Marginal cost: M%28300%29+=+400+-+.2%28300%29 -------> M(300) = 400 - 60, or highlight_green%28matrix%281%2C2%2C+%22M%28300%29+=%22%2C+%22%24340%22%29%29