SOLUTION: Someone help please, it says. Use synthetic division to solve : x^5-4x^4-2x^3+4x^2+x=0 Show work please. Thanks

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Question 1013109: Someone help please, it says.
Use synthetic division to solve : x^5-4x^4-2x^3+4x^2+x=0
Show work please. Thanks
Found 3 solutions by addingup, fractalier, MathTherapy:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website!
x^5-4x^4-2x^3+4x^2+x=0 divided by what?
This should be, for example:
x^5-4x^4-2x^3+4x^2+x/x+4
---------------------------------------
The number you are looking for should be something like x+4. Look it up and re-post the problem.

Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website!
From x^5 - 4x^4 - 2x^3 + 4x^2 + x = 0, we c an see that x factors out and gives
x(x^4 - 4x^3 - 2x^2 + 4x + 1) = 0
which means x = 0.
If we inspect this remaining factor, we can see x = 1 is a root also...so let us synthetically divide by -1...
-1] 1 -4 -2 4 1
-1 5-3 -1
-------------------
1 -5 3 1
so what remains is x^3 - 5x^2 - 3x + 1 = 0
Then continue the process if possible...

Answer by MathTherapy(10551)   (Show Source):
You can put this solution on YOUR website!

Someone help please, it says.
Use synthetic division to solve : x^5-4x^4-2x^3+4x^2+x=0
Show work please. Thanks

--- Factoring out GCF, x -------- Factoring out GCF, x Using the RATIONAL ROOT THEOREM we find that 2 roots are: Use synthetic division with a divisor/root of 1 1 | 1 - 4 - 2 + 4 + 1 | + 1 - 3 - 5 - 1 -------------------------- 1 - 3 - 5 - 1 0

Now we have:

Use synthetic division with a divisor/root of - 1 - 1 | 1 - 3 - 5 - 1 | - 1 + 4 + 1 ---------------------- 1 - 4 - 1 0

Now we have:

does not have any INTEGER roots, so you can use the following to get the final 2 roots: 1) the quadratic equation 2) completing the square 3) graphing