SOLUTION: The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g=10m/s find;
The initial velocity of the projectile,
The greatest height reached by the
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The initial velocity of the projectile,
The greatest height reached by the
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Question 1013069: The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g=10m/s find;
The initial velocity of the projectile,
The greatest height reached by the projectile,
The time of flight,
The range of the projectile.
You can put this solution on YOUR website! The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g=10m/s find;
The initial velocity of the projectile
= sqrt(6^2 + 8^2) = 10 m/sec
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The greatest height reached by the projectile
h(t) = -10t^2 + 6t
h'(t) = -20t + 6 = 0 at max
t = 0.3 second
h(0.3) = 0.9 meters
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The time of flight
= 2*tmax
= 0.6 seconds
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The range of the projectile.
= 0.6*8
= 4.8 meters
You can put this solution on YOUR website! .
The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g = 10 m/s. Find
The initial velocity of the projectile
= sqrt(6^2 + 8^2) = 10 m/sec
----------------
The greatest height reached by the projectile
h(t) =
h'(t) = -10t + 6 = 0 at max
t = 0.6 second to get the greatest height.
h(0.6) = 1.8 meters
-------------
The time of flight
= 2*tmax
= 1.2 seconds
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