SOLUTION: 4) It’s a mystery what’s inside this container. But you won’t look, you’re not a complainer. Seventeen coins, that is a hint from me to you. Quarters and dimes, some old and som

Algebra ->  Equations -> SOLUTION: 4) It’s a mystery what’s inside this container. But you won’t look, you’re not a complainer. Seventeen coins, that is a hint from me to you. Quarters and dimes, some old and som      Log On


   



Question 1007579: 4) It’s a mystery what’s inside this container.
But you won’t look, you’re not a complainer.
Seventeen coins, that is a hint from me to you.
Quarters and dimes, some old and some new.
The total inside is 3.35.
Get busy on this problem, come on look alive.
You are smarter than you think, you’ve got the knowledge
To solve problems like this and then go to college.

Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
It’s a mystery what’s inside this container.
But you won’t look, you’re not a complainer.
Seventeen coins, that is a hint from me to you.
Quarters and dimes, some old and some new.
The total inside is 3.35.
--------------
q + d = 17
25q + 10d = 335
---
Solve for q & d
I would use substation.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = number of dimes
Let +q+ = number of quarters
---------------------------
(1) +d+%2B+q+=+17+
(2) +10d+%2B+25q+=+335+ ( in cents )
----------------------
Multiply both sides of (1) by +10+
and subtract (1) from (2)
(2) +10d+%2B+25q+=+335+
(1) +-10d+-+10q+=+-170+
-------------------------
+15q+=+165+
+q+=+11+
and
(1) +d+%2B+q+=+17+
(1) +d+%2B+11+=+17+
(1) +d+=+6+
----------------
There are 6 dimes and 11 quarters
----------------
check:
(2) +10d+%2B+25q+=+335+
(2) +10%2A6+%2B+25%2A11+=+335+
(2) +60+%2B+275+=+335+
(2) +335+=+335+
OK