SOLUTION: A bicyclist rode into the country for 5 hours. In returning, her speed was 5 miles per hour faster and the trip took 4 hours. What was her speed each way?

Algebra ->  Equations -> SOLUTION: A bicyclist rode into the country for 5 hours. In returning, her speed was 5 miles per hour faster and the trip took 4 hours. What was her speed each way?      Log On


   



Question 100721: A bicyclist rode into the country for 5 hours. In returning, her speed was 5 miles per hour faster and the trip took 4 hours. What was her speed each way?
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
These types of problems require you to comprehend the equality. In this case, the rider rides the same distance in each direction. The general distance equation is d = rate * time. We don't know the rate, so let's call it r. Let d stand for the distance traveled. We are told the time in each direction. But going one way the speed was r+5.
5r+=+d+=+4%2A%28r%2B5%29
That simplifies to
5r+=+4r+%2B+20
Subtracting 4r from both sides
r+=+20 and r%2B5+=+25, which are the speeds outbound and inbound.
ALWAYS check! 5%2A20+=+100+=+4%2A25. Check.