SOLUTION: Find the smallest possible integer when divided by either 3,4 or 5 with a remainder of 2.

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Question 1001840: Find the smallest possible integer when divided by either 3,4 or 5 with a remainder of 2.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x must be divisible by 3,4,5
Hence
x=n%2ALCM%283%2C4%2C5%29=n%2A60
So x=60n for any integer n.
since the problem asks for the "smallest positive" such number, the answer is:
x=60%2A1 or
+x=60+=> smallest number divisible by 3,4,5
since we also have reminder of 2, your number is
x%2B2=62
check:
62%2F3=20 and reminder 2
62%2F4=15 and reminder 2
62%2F5=12 and reminder 2