SOLUTION: Write an equation: Vertex is (5,4) Focus is (8,4)

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Question 1001602: Write an equation:
Vertex is (5,4)
Focus is (8,4)

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Write an equation of the parabola with vertex (3, 1) and focus (3, 5).
Write an equation:
Vertex is (5,4)
Focus is (8,4)
The equation of a parabola with vertex (h,k) is either
%28x+-+h%29%5E2+=+4p%28y+-+k%29+
or
%28y+-+k%29%5E2+=+4p%28x+-+h%29
where the vertex is (h,k), p is distance from vertex to focus
Since the vertex is (5,4), h+=+5 and k+=+4.
Since the vertex (5,4) and focus (8,4) have the same y-coordinate, it is equation of the second type.
%28y+-+k%29%5E2+=+4p%28x+-+h%29
The distance from vertex to focus is 3 units. Since the focus is right of the vertex, p is positive, and so p+=+3. (Parabola opens to the right)
So the equation is
%28y+-+4%29%5E2+=+4%2A3%28x+-+5%29
%28y+-+4%29%5E2+=+12%28x+-+5%29

%28y+-+4%29%5E2%2F12+=+x+-+5

%281%2F12%29%28y+-+4%29%5E2%2B5+=+x+
it cannot be this:
x= 1/4c y^2 (x-h)^2 + k....here is something wrong