Question 1000527: Use the bisection to find the positive root of the equation to the nearest tenth.
x^2-11=0 (Show procedures) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use the bisection to find the positive root of the equation to the nearest tenth.
x^2-11=0 (Show procedures)
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Factor::
(x-sqrt(11))(x+sqrt(11)) = 0
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x = sqrt(11) or x = -sqrt(11)
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3^2 < 11 < 4^2
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a------b-----(a+b)/2---[(a+b)/2]^2
3------4------3.5-------3.5^2 = 12.25---- > 11
3-----3.5-----3.25------3.25^2 = 10.56---- < 11
3.25--3.5-----3.375-----3.375^2 = 11.39---- > 11
etc
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sqrt(11) = 3.32
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-sqrt(11) = -3.32
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Cheers,
Stan H.
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