SOLUTION: Find the smallest natural number that is divisible by 2 and by 3, and which is simultaneously the fourth power of an integer, and the sixth power of an integer.

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Question 809289: Find the smallest natural number that is divisible by 2 and by 3, and which
is simultaneously the fourth power of an integer, and the sixth power of an integer.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
4th and 6th power ---> LCM(4, 6) = 12 ---> 12th power

2^12 * 3^12 = (2 * 3)^12 = 6^12