SOLUTION: If g(x)=3x-5, determine the function of ƒ for which g(ƒ(x))=15x^2-6x+4.

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Question 770736: If g(x)=3x-5, determine the function of ƒ for which g(ƒ(x))=15x^2-6x+4.
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
If g(x)=3x-5, determine the function of ƒ for which g(ƒ(x))=15x^2-6x+4.
g(ƒ(x))= 3f(x)-5 =15x^2-6x+4
f(x) = (15x^2-6x+4+5)/3 = 5x^2-2x+3
Answer: f(x)=5x^2-2x+3
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