SOLUTION: For any integer x, prove that x² ≥ 0

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Question 1193909: For any integer x, prove that x² ≥ 0
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

If x = 0, then x^2 = x*x = 0*0 = 0. This satisfies the "or equal to" part of x%5E2+%3E=+0

If x < 0, then we have (negative)*(negative) = positive

If x > 0, then (positive)*(positive) = positive

If x is nonzero, then x^2 is positive.

Therefore, if x is any integer, then x%5E2+%3E=+0 aka x^2 is nonnegative.