SOLUTION: Find the points of intersection of the parabola y = −2 (x + 1)^2 − 5, where y = f(x), x ∈ R, and the straight line y = mx − 7, where y = f(x), x ∈ R.

Algebra ->  Divisibility and Prime Numbers  -> Lessons -> SOLUTION: Find the points of intersection of the parabola y = −2 (x + 1)^2 − 5, where y = f(x), x ∈ R, and the straight line y = mx − 7, where y = f(x), x ∈ R.      Log On


   

Question 1088371: Find the points of intersection of the parabola y = −2 (x + 1)^2 − 5, where y = f(x), x ∈ R, and the straight line y = mx − 7, where y = f(x), x ∈ R.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
-2%28x%2B1%29%5E2-5=mx-7
-2%28x%5E2%2B2x%2B1%29-5=mx-7
-2x%5E2-4x-2-5-mx%2B7=0
-2x%5E2-%284%2Bm%29x=0
-x%282x%2B%284%2Bm%29%29=0
x%282x%2B%284%2Bm%29%29=0
Two zeros:
x=0
and
2x=-%284%2Bm%29
x=%284%2Bm%29%2F2
x=-%282%2Bm%2F2%29
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Example: When m=2, the zeroes are x=0
and x=-%282%2B2%2F2%29=-%282%2B1%29=-3
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