SOLUTION: I have created a method that tests divisibility by 7 and 13. It reduces an integer (doesn't matter its extension) to a two-digit number. Original number and reduced number divided

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Question 10288: I have created a method that tests divisibility by 7 and 13.
It reduces an integer (doesn't matter its extension) to a two-digit number. Original number and reduced number divided by 7 will leave the same remainder.
I would like to have your opinion about my method that is available at the site: www.7and13divisibility.com
My best regards
Silvio Moura Velho
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
Silvio,

I have had a quick look at your website and your description is painful to read :-) but it looks like a very good method.

I shall bookmark the site and have a proper read some time soon :-)

Jon.