This Lesson (Restore the omitted digit in a number in a way that the number is divisible by 9) was created by by ikleyn(52906)  : View Source, ShowAbout ikleyn:
Restore the omitted digit in a number in a way that the number is divisible by 9
Problem 1In the number 12345_67 one digit was omitted, and you see the blank placeholder in the corresponding position.
Restore the digit in the number in a way that the number is divisible by 9.
Solution
The "divisibility by 9 rule" says: the number is divisible by 9 if and only if the sum of its digits is divisible by 9.
See the lesson Divisibility by 9 rule in this site.
In our case the sum of digits is
1 + 2 + 3 + 4 + 5 + x + 6 + 7 = 28 + x,
where x stands for the unknown digit.
So, x should be 8 for the sum is divisible by 9, and there is no other opportunity.
Thus there is only one solution: the restored digit is 8 and, hence, the restored number is 12345867.
Solve yourself the next problem.
Problem 2In the number 12345_678 one digit was omitted, and you see the blank placeholder in the corresponding position.
Restore the digit in the number in a way that the number is divisible by 9.
Is the solution unique? How many solutions are there?
My other lessons in this site on divisibility numbers are
- Divisibility by 2 rule
- Divisibility by 3 rule
- Divisibility by 4 rule
- Divisibility by 5 rule
- Divisibility by 6 rule
- Divisibility by 9 rule
- Divisibility by 10 rule
- Divisibility by 11 rule
- Restore the omitted digit in a number in a way that the number is divisible by 11
- Can there be a perfect square ?
- Math circle level problems on divisibility numbers
- Math circle level problem on restoring digit in the product of two 16-digit numbers
- Math circle level problem on finding remainders
- OVERVIEW of Divisibility rules by 2, 3, 4, 5, 6, 9, 10 and 11
This lesson has been accessed 2685 times.
|