Lesson Restore the omitted digit in a number in a way that the number is divisible by 9

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Restore the omitted digit in a number in a way that the number is divisible by 9


Problem 1

In the number 12345_67 one digit was omitted,  and you see the blank placeholder in the corresponding position.
Restore the digit in the number in a way that the number is divisible by  9.

Solution

The  "divisibility by 9 rule"  says:  the number is divisible by  9  if and only if the sum of its digits is divisible by  9.
See the lesson  Divisibility by 9 rule  in this site.

In our case the sum of digits is

1 + 2 + 3 + 4 + 5 + x + 6 + 7 = 28 + x,

where  x  stands for the unknown digit.

So,  x  should be  8  for the sum is divisible by  9,  and there is no other opportunity.
Thus there is only one solution:  the restored digit is  8  and,  hence,  the restored number is  12345867.


Solve yourself the next problem.

Problem 2

In the number 12345_678 one digit was omitted,  and you see the blank placeholder in the corresponding position.
Restore the digit in the number in a way that the number is divisible by  9.
Is the solution unique?  How many solutions are there?


My other lessons in this site on divisibility numbers are

    - Divisibility by 2 rule
    - Divisibility by 3 rule
    - Divisibility by 4 rule
    - Divisibility by 5 rule
    - Divisibility by 6 rule
    - Divisibility by 9 rule
    - Divisibility by 10 rule
    - Divisibility by 11 rule
    - Restore the omitted digit in a number in a way that the number is divisible by 11
    - Can there be a perfect square ?
    - Math circle level problems on divisibility numbers
    - Math circle level problem on restoring digit in the product of two 16-digit numbers
    - Math circle level problem on finding remainders
    - OVERVIEW of Divisibility rules by 2, 3, 4, 5, 6, 9, 10 and 11


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