SOLUTION: Prove : Two numbers when divided by a certain divisior give remainders r1 and r2. When their sum is divided by the same divisor, the remainder is r3. The divisor is given by r1 + r

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: Prove : Two numbers when divided by a certain divisior give remainders r1 and r2. When their sum is divided by the same divisor, the remainder is r3. The divisor is given by r1 + r      Log On


   



Question 892364: Prove : Two numbers when divided by a certain divisior give remainders r1 and r2. When their sum is divided by the same divisor, the remainder is r3. The divisor is given by r1 + r2 - r3
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
This is not always true. Suppose our divisor is 10 and the two numbers are 11 and 21. Then r1, r2 = 1, 1 and r3 = 2. The divisor is not 1 + 1 - 2 = 0.

However, it is true that r1 + r2 - r3 is a multiple of the divisor.