SOLUTION: The number 2^48 - 1 divisible by two numbers between 60 and 70. Their sum is: (a) 124 (b) 128 (c) 132 (d) 136 (e) None of the above

Question 353100: The number 2^48 - 1 divisible by two numbers between 60 and 70. Their sum is:
(a) 124 (b) 128 (c) 132 (d) 136 (e) None of the above

Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
The number 2^48 - 1 divisible by two numbers between 60 and 70. Their sum is:
(a) 124 (b) 128 (c) 132 (d) 136 (e) None of the above

http://www.wolframalpha.com/input/?i=factor+%282%5E48%29-1
(used factor 2^48 - 1 to get factors)

prime factorization: 3^2 * 5 * 7 * 13 * 17 * 97 * 241 * 257 * 673
this gives 768 divisors according to wolframalpha
here is the ones up to 105:
1,3,5,7,9,13,15,17,21,35,39,45,51,63,65,85,91,97,105

the 2 numbers between 60 and 70 are 63 and 65
63 + 65 = 128, answer is (b) 128

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