Lesson Can there be a perfect square ?

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Can there be a perfect square ?


Problem 1

Can there be a perfect square whose digits consist of exactly  4  ones,  4  twos and  4  zeros in any order?

Solution


Let N = n%5E2 be such a number.


Since the sum of digits of the number  " N "   4*1 + 4*2 +4*0 = 4 + 8 + 0 = 12  is divisible by 3,

it implies that the number N itself is divisible by 3  (the "divisibility by 3 rule").



In turn, it implies that the number " n "  itself  is divisible by 3.



Then the number  n%5E2  is divisible by 3^2 = 9;  hence, the number N  is divisible by 9.



But the sum of the digits of the number N, which was calculated above as 12, is not divisible by 9.


It contradicts to the "divisibility by 9 rule". 


Hence, such a number N with assigned properties DOES NOT EXIST.


The proof is completed.

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On divisibility rules by 3 and by 9 see the lessons
    - Divisibility by 3 rule
    - Divisibility by 9 rule
in this site.


My other lessons in this site on divisibility numbers are

    - Divisibility by 2 rule
    - Divisibility by 3 rule
    - Divisibility by 4 rule
    - Divisibility by 5 rule
    - Divisibility by 6 rule
    - Divisibility by 9 rule
    - Divisibility by 10 rule
    - Divisibility by 11 rule
    - Restore the omitted digit in a number in a way that the number is divisible by 9
    - Restore the omitted digit in a number in a way that the number is divisible by 11
    - Math circle level problems on divisibility numbers
    - Math circle level problem on restoring digit in the product of two 16-digit numbers
    - Math circle level problem on finding remainders
    - OVERVIEW of Divisibility rules by 2, 3, 4, 5, 6, 9, 10 and 11


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