SOLUTION: {{{(x + 1)^2}}}= 9 {{{( 3x + 2 )^2}}}=49

Algebra ->  Decimal-numbers -> SOLUTION: {{{(x + 1)^2}}}= 9 {{{( 3x + 2 )^2}}}=49      Log On


   

Question 7791: %28x+%2B+1%29%5E2= 9
%28+3x+%2B+2+%29%5E2=49
Answer by bonster(299) About Me  (Show Source):
You can put this solution on YOUR website!
%28x+%2B+1%29%5E2= 9
(x+1)(x+1)=9
x%5E2%2B2x%2B1=9
x%5E2%2B2x-8=0
(x-2)(x+4)=0
*****if x-2=0, x=2
*****if x+4=0, x=-4

%28+3x+%2B+2+%29%5E2=49
(3x+2)(3x+2)=49
9x%5E2%2B6x%2B6x%2B4=49
9x%5E2%2B12x-45=0
3%283x%5E2%2B4x-15%29=0
3%28x%2B3%29%283x-5%29=0
*****if x+3=0, then x=-3
*****if 3x-5=0, then x=3%2F5