SOLUTION: 2√27x^5y

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Question 184502: 2√27x^5y
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2%2Asqrt%2827%2Ax%5E5y%29 Start with the given expression


2%2Asqrt%289%2A3%2Ax%5E5y%29 Factor 27 into 9%2A3. Note: one of the factors is a perfect square.

2%2Asqrt%289%2A3%2Ax%5E2%2Ax%5E2%2Ax%2Ay%29 Factor x%5E5 into x%5E2%2Ax%5E2%2Ax.


Break up the square root.


2%2A3%2Asqrt%283%29%2Asqrt%28x%5E2%29%2Asqrt%28x%5E2%29%2Asqrt%28x%29%2Asqrt%28y%29 Take the square root of 9 to get 3


2%2A3%2Asqrt%283%29%2Ax%2Ax%2Asqrt%28x%29%2Asqrt%28y%29 Take the square root of x%5E2 to get "x". Note: x%3E=0


6x%5E2%2Asqrt%283xy%29 Multiply and rearrange the terms.


So 2%2Asqrt%2827%2Ax%5E5y%29=6x%5E2%2Asqrt%283xy%29 where every variable is nonnegative