SOLUTION: I wasn't sure what to list this under because it's not algebra, it's just confusing! I need to know how many zeros will be on the right side if you multiply 50x51x52x....x198x199x

Algebra ->  Decimal-numbers -> SOLUTION: I wasn't sure what to list this under because it's not algebra, it's just confusing! I need to know how many zeros will be on the right side if you multiply 50x51x52x....x198x199x      Log On


   

Question 163488This question is from textbook Mathematics for Elementary Teachers: A Conceptual Approach
: I wasn't sure what to list this under because it's not algebra, it's just confusing! I need to know how many zeros will be on the right side if you multiply 50x51x52x....x198x199x200. This question is from textbook Mathematics for Elementary Teachers: A Conceptual Approach

Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
number of zeros = number of factors of 5 in the product

50 * 51 * ... * 200 = (200!)/(49!)

number of zeros in 200! = 200/5 + 200/5^2 + ... = 49 (must be an integer)
number of zeros in 49! = 49/5 + 49/5^2 + ... = 10 (must be an integer)

number of zeros in 50 * 51 * ... * 200 = 49 - 10 = 39 zeroes