SOLUTION: The table shows that approximate population of the world in the past centuries. YEAR WORLD POPULATION 1549 4.20x10^8 1649 5.45x10^8 1749 7.28x10^8 184

Algebra ->  Decimal-numbers -> SOLUTION: The table shows that approximate population of the world in the past centuries. YEAR WORLD POPULATION 1549 4.20x10^8 1649 5.45x10^8 1749 7.28x10^8 184      Log On


   



Question 1125559: The table shows that approximate population of the world in the past centuries.
YEAR WORLD POPULATION
1549 4.20x10^8
1649 5.45x10^8
1749 7.28x10^8
1849 1.17x10^9
Find,
i) the number of times that the population in 1849 is as large as that in 1649,
ii) the number of times that the population of China is as large as that of the world in 1749 given that the population of China in year 2000 is approximately 1.23 billion where 1 billion = 10^9

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
"number of times as large" indicates you will need to divide:
i) +%281.17%2A10%5E9%29+%2F+%285.45%2A10%5E8%29+ = (approx) 2.147


ii) +%281.23%2A10%5E9%29+%2F+%287.28%2A10%5E8%29+ = (approx) 1.690