SOLUTION: Two gears rotate so that one completes 1 more revolution per minute than the other. If it takes the smaller gear 1 second less than the larger gear to complete 1/5 revolution, how

Algebra ->  Decimal-numbers -> SOLUTION: Two gears rotate so that one completes 1 more revolution per minute than the other. If it takes the smaller gear 1 second less than the larger gear to complete 1/5 revolution, how      Log On


   



Question 1114309: Two gears rotate so that one completes 1 more revolution per minute than the other. If it takes the smaller gear 1 second less than the larger gear to complete 1/5 revolution, how many revolutions does each gear make in 1 minute?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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Answer.  Faster gear makes 4 revolutions per minute, while the slower gear makes 3 revolutions per minute.


Check.  The faster gear makes one revolution in 60/4 = 15 seconds.

        The slower gear makes one revolution in 60/3 = 20 seconds.


        Difference of times to make 1/5 revolution is  (20-15)/5 = 1 second.

Solution

Let n be the number of rotations of the faster gear per minute.

Then the number of rotations of the slower gear per minute is (n-1),  according to the condition.


The time to make one rotation for faster gear is  1%2Fn  of an minute for the faster gear  and  1%2F%28n-1%29  of an minute for the slower gear.


The difference  1%2F%28n-1%29 - 1%2Fn  is equal to 5 seconds,  or  5%2F60  of the minute,  according to the condition.


So, the equation is


1%2F%28n-1%29 - 1%2Fn = 5%2F60,


and when you solve it, you will get the answer claimed above.