SOLUTION: Find the max/min point for the following function: f (x,y) = x^3 + y^3 + 6xy

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Question 1035337: Find the max/min point for the following function:
f (x,y) = x^3 + y^3 + 6xy

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%2Cy%29%5Bx%5D+=+3x%5E2%2B6y and f%28x%2Cy%29%5By%5D+=+3y%5E2%2B6x.
Also, f%5Bxx%5D+=+6x and f%5Byy%5D+=+6y, and f%5Bxy%5D=+f%5Byx%5D+=+6
Use the Second partial derivative test.
Set the partial derivatives above to 0 and solve for x and y.
3x%5E2%2B6y+=+0 and +3y%5E2%2B6x+=+0.
This system of equations yield two points as its solutions: (0,0) , (-2,-2). (Verify!!)
Now find the determinant of the hessian for each point.
For (0,0): f%5Bxx%5D%2Af%5Byy%5D+-+%28f%5Bxy%5D%29%5E2+=+0%2A0-6%5E2+=+-36+%3C+0.
This implies that the point (0,0) is a saddle point (neither a local max nor a local min).
For (-2,-2): f%5Bxx%5D%2Af%5Byy%5D+-+%28f%5Bxy%5D%29%5E2+=+-12%2A-12-6%5E2+=+144-36+%3E+0.
Since f%5Bxx%5D+%3C+0, it follows that (-2,-2) is a local maximum.