Lesson Two types of tickets at two different prices...

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If *[tex \LARGE x] items are sold for a price of *[tex \LARGE p_1] each, *[tex \LARGE y] items are sold for a price of *[tex \LARGE p_2] each, the total, *[tex \LARGE T] of items were sold, and the total revenue from the sale was *[tex \LARGE R], then:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ T]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p_1x\ +\ p_2y\ =\ R]

Solve the 2X2 system by substitution:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ T\ -\ x]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p_1x\ +\ p_2(T\ -\ x)\ =\ R]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (p_1\ -\ p_2)x\ =\ R\ -\ p_2T]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{R\ -\ p_2T}{p_1\ -\ p_2]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ T\ -\ \frac{R\ -\ p_2T}{p_1\ -\ p_2]

John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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