SOLUTION: The concession stand sold 36 cans of juice. There were 13 fewer cans of soda sold than cans of juice and 10 fewer bottles of water sold than cans of soda. How many bottles of wat

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The concession stand sold 36 cans of juice. There were 13 fewer cans of soda sold than cans of juice and 10 fewer bottles of water sold than cans of soda. How many bottles of wat      Log On


   

Question 795176: The concession stand sold 36 cans of juice. There were 13 fewer cans of soda sold than cans of juice and 10 fewer bottles of water sold than cans of soda. How many bottles of water were sold?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
j for juice
s for soda
w for water

Translating from the descriptions,
---------------------
j=36.
---------------------
s=j-13.
---------------------
w=s-10.
---------------------
Try to see how those make sense, before continuing.

Do you want to use a matrix to solve, or do you want to use just substitutions and simplifications to solve? You have a system of three equations in three unknown variables.

Simplest step first can be substitute for j=36 in the s and the w equations.
s=36-13 and w=s-10
Obviously one of these is affected but not the other one. Simplify s, and then substitute it into the w equation:
s=23.
w=23-10
highlight%28w=13%29. Very Neat! Solved for w.
Thirteen bottles of water sold.