SOLUTION: the sum of the digits of a three digit number is 9. if the digits are reversed the number increases by 495. Find the number if the sum of the tens and hundreds digits is half the u

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the sum of the digits of a three digit number is 9. if the digits are reversed the number increases by 495. Find the number if the sum of the tens and hundreds digits is half the u      Log On


   

Question 791003: the sum of the digits of a three digit number is 9. if the digits are reversed the number increases by 495. Find the number if the sum of the tens and hundreds digits is half the units digit.







Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the digits of a three digit number is 9. if the digits are reversed the number increases by 495. Find the number if the sum of the tens and hundreds digits is half the units digit.
let u=units digit
let t=tens digit
let h=hundreds digit
..
h+t+u=9
h+t=u/2
(u/2)+u=9
3u/2=9
3u/18
u=6
original number:
100h+10t+6
..
reversed number:
600+10t+h
..
reverse-original number=495
600+10t+h-(100h+10t+6)=495
594-99h=495
99h=99
h=1
t=9-h-u=9-7=2
original number:100h+10t+6=126
reversed number=621
check:621-126=495