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| Question 739216:  ankita travel 14 km to home partially by rickshaw AND BY BUS SHE TAKES 1 2 HR IF SHE TRAVELS BY RICKSHAW AND THE REMAING DISTANCE BY BUS ON OTHER HAND IF SHE TRAVELS 4 KM BY RICKSHAW AND REMAING DISTANCE BY BUS SHE TAKES 9 MINUTES LONGER
 
 
 
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! Will try to make sense of this. :
 Ankita travel 14 km home, partially by rickshaw and by bus.
 :
 She takes
  hr if is she travels 4 km by Rickshaw and takes the remaining distance by by bus. :
 On the other hand, if she travels 10 km by rickshaw, and the remaining distance by bus, she takes 9 min longer.
 :
 Assume you want to find the speed of the rickshaw and speed of the bus.
 :
 let r = speed of the rickshaw
 let b = speed of the bus
 :
 Write an time equation for the 1st statement (time = dist/speed):
 "She takes
  hr if is she travels 4 km by Rickshaw and takes the remaining distance by by bus." 
  +  =  multiply equation by 2rb, to get rid of the denominators
 2rb*
  + 2rb*  = 2rb*  cancel the denominators
 8b + 20r = rb
 :
 Write a time equation for the 2nd statement (time = dist/speed):
 "if she travels 10 km by rickshaw, and the remaining distance by bus, she takes 9 min longer."
 
  +  = 30 + 9 
  +  = 39 change 39 min to hr (we're finding the speed in km/hr
 
  +  =  
  +  =  multiply equation by 20rb, to get rid of the denominators
 20rb*
  + 20rb*  = 20rb*  cancel the denominators
 200b + 80r = 13rb
 :
 multiply the first equation by 4, subtract from the above equation
 200b + 80r = 13rb
 32b + 80r =  4rb
 -----------------
 168b = 9rb
 divide both sides by by b
 168 = 9r
 r = 168/9
 r =  18.67 km/hr  is the speed of the rickshaw (Is that possible?)
 :
 Find the speed of the bus
 8b + 20r = rb
 8b + 20(18.67) = 18.67b
 373.3 = 18.67b - 8b
 373.3 = 10.67b
 b = 373.3/10.67
 b ~ 35 km/hr is the speed of the bus
 :
 :
 See if that checks out in the first statement, find the travel time of each
 
  +  = .214 + .286 = .5 hrs
 
 
 
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