You can put this solution on YOUR website! x + y = 10, x = 10-y
x^2 + y^2 = 68
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Substitute x into the second equation
(10-y)^2 + y^2 = 68
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(10-y)(10-y) + y^2 = 68
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100 - 10y - 10y + y^2 + y^2 = 68
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100 - 20y + 2y^2 = 68
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2y^2 - 20y + 32 = 0
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(2y-4)(y-8)
2y-4=0, so y = 2
y-8=0, so y = 8
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The numbers are and
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Check
perimeter:
area:
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