SOLUTION: in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the thi

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the thi      Log On


   

Question 623761: in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than the first day, then how many hours did he drive each day ?
Answer by MathTherapy(10552) About Me  (Show Source):
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in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than the first day, then how many hours did he drive each day ?

Let time he drove on 1st day be T
Then time he drove on 3rd day = T + 4
Time he drove on 2nd day = 36 – (T + T + 4), or 36 – 2T – 4, or 32 – 2T

Distance on 1st day, plus distance on 2nd day, plus distance on 3rd day = total distance,
OR

64(T) + 62(32 – 2T) + 58(T + 4) = 2,196
64T + 1,984 – 124T + 58T + 232 = 2,196
64T – 124T + 58T = 2,196 – 1,984 – 232
– 2T = - 20
T, or time he drove on 1st day = %28-+20%29%2F-+2, or highlight_green%2810%29 hours

Time driven on 2nd day = 32 – 2T, or 32 – 2(10), or 32 – 20, or highlight_green%2812%29 hours

Time driven on 3rd day = T + 4, or 10 + 4, or highlight_green%2814%29 hours

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