SOLUTION: A jeweler has five rings, each weighing 18 grams made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to
Question 620069: A jeweler has five rings, each weighing 18 grams made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 75%. How much pure silver must be added for the mixture to have a gold content of 75%? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A jeweler has five rings, each weighing 18 grams made of an alloy of 10% silver and 90% gold.
He decides to melt down the rings and add enough silver to reduce the gold content to 75%.
How much pure silver must be added for the mixture to have a gold content of 75%?
:
Find the total weight of the rings: 5 * 18 = 90 grams
:
let s = amt of silver required to accomplish this
:
.90(90) = .75(s + 90)
81 = .75s + 67.5
81 - 67.5 = .75s
13.5 = .75s
s =
s = 18 grams of silver
