SOLUTION: find two numbers such that the sum of twice the first and the second is 92, and four times the first exceeds seven times the second by 2.

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Question 610110: find two numbers such that the sum of twice the first and the second is 92, and four times the first exceeds seven times the second by 2.
Answer by flame8855(424) About Me  (Show Source):
You can put this solution on YOUR website!
2x+3y=92
4x=7y+2
-4x-6y=-184
4x-7y=2
-13y=-182
y = 14
x= 25