Question 58762This question is from textbook college algebra
: Please help me solve. It involves systems of equations. Thank you
During summer vacation Hector and Ann earned a total of $1088. Hector worked 8 days fewer than Ann and earned $2 per day less. Find the number of days he worked and the daily wage he made if the total number of days worked by both was 72.
Thanks!
This question is from textbook college algebra
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! During summer vacation Hector and Ann earned a total of $1088. Hector worked 8 days fewer than Ann and earned $2 per day less. Find the number of days he worked and the daily wage he made if the total number of days worked by both was 72.
:
Find out how many days each worked:
:
Number of days worked by Ann = x
:
"Hec worked 8 days fewer than Ann"
Hecs days = (x-8)
:
Together they worked 72 days:
x + (x-8) = 72
2x = 72 + 8
2x = 80
x = 80/2
x = 40 days worked by Ann, then Hec worked 32 days
:
Find out how much they made:
:
Let w = Ann's daily wage
Then (w-2) = Hec daily wage
:
40w + 32(w-2) = 1088
40w + 32w - 64 = 1088
72w = 1088 + 64
72w = 1152
w = 1152/72
w = $16 a day is Ann's wage, then $14 a day is Hec's wage
:
Check on your calc: (40*16) + 32(14) = 1088
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