SOLUTION: When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 , where v is the initial upwards velocity in feet per second. If v=34 feet per s

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 , where v is the initial upwards velocity in feet per second. If v=34 feet per s      Log On


   

Question 49292: When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 , where v is the initial upwards velocity in feet per second. If v=34 feet per second, find all values of t for which h=16 feet. Do not round any intermediate steps. Round your answer to 2 decimal places.
Answer by venugopalramana(3286) About Me  (Show Source):
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When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 , where v is the initial upwards velocity in feet per second. If v=34 feet per second, find all values of t for which h=16 feet. Do not round any intermediate steps. Round your answer to 2 decimal places.
h=vt-16t^2
16=34T-16T^2
8T^2-17T+8=0
T=[17+ OR - SQRT(17^2-4*8*8)]/(2*8)=1.42...OR....0.70 SEC