SOLUTION: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller       Log On


   

Question 482019: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller part. What is the smaller part of the investment?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
.06p=.05(10000-p)+160
6p=5(10000-p)+16000
6p=50000-5p+16000
11p=66000
p=6000
$6000 was invested at 6%, and $4000 was invested at 5%..