SOLUTION: Heather's school is charging $12 per uniform plus $200 fees and Brandon's School is charging $14 per uniform plus $196 fees C = 12n + 200 C = 14n + 196 When will the two equ

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Heather's school is charging $12 per uniform plus $200 fees and Brandon's School is charging $14 per uniform plus $196 fees C = 12n + 200 C = 14n + 196 When will the two equ      Log On


   

Question 430534: Heather's school is charging $12 per uniform plus $200 fees and Brandon's School is charging $14 per uniform plus $196 fees
C = 12n + 200
C = 14n + 196
When will the two equations break even? Use substitution or elimination method
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

C = 12n + 200

C = 14n + 196 



C = 12n + 200

-C = -14n - 196 

0 = -2n - 4

 n = 2 

If Heather and Brandon each purchased 2 uniforms, their cost would be the same

  12*2 + 200 = $224 = 14*2 + 196 

  Heather               Brandon