SOLUTION: An elephant herd is moving at a rate of 6 mph. a stray ran at 10mph and caught up in five minutes. How long(in hours) did the stray run to catch up and how far did it run?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An elephant herd is moving at a rate of 6 mph. a stray ran at 10mph and caught up in five minutes. How long(in hours) did the stray run to catch up and how far did it run?       Log On


   

Question 345384: An elephant herd is moving at a rate of 6 mph. a stray ran at 10mph and caught up in five minutes. How long(in hours) did the stray run to catch up and how far did it run?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate*Time=Distance
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5 minutes=5%2F60=1%2F12 hour
So the stray ran (1%2F12) hour.
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HX is the distance that the herd moved.
In 5 minutes, the herd moved,
HX=6%281%2F12%29=1%2F2mile
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SX is the distance that the stray moved.
In 5 minutes, the stray moved,
SX=10%281%2F12%29
SX=10%2F12=5%2F6
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SH is the distance they were intially separated.
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SH%2BHX=SX
SH%2B1%2F2=5%2F6
SH=5%2F6-3%2F6
SH=2%2F6=1%2F3 mile