SOLUTION: A cashier at Apex Parts received a check for $2380 for 59 parts. The parts cost $20 and $50 but the number wanted of each wasn't given. How many of each can be bought with that a

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A cashier at Apex Parts received a check for $2380 for 59 parts. The parts cost $20 and $50 but the number wanted of each wasn't given. How many of each can be bought with that a      Log On


   

Question 33976: A cashier at Apex Parts received a check for $2380 for 59 parts. The parts cost $20 and $50 but the number wanted of each wasn't given. How many of each can be bought with that amount?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the number that can be bought for $20.00 each, then (59-x) = the number that can be bought for $50.00 each. You can write:
$20(x) + $50(59-x) = $2380 Simplify and solve for x.
$20(x) + $2950 - $50x = $2380
-$30(x) + $2950 = $2380 Subtract $2950 from both sides.
-$30(x) = -$570 Divide both sides by -$30.
x = 19
59-x = 40
19 can be bought at $20.00 each
40 can be bought at $50.00 each.