SOLUTION: 5. An accountant walks part of the way and takes the bus the remaining part of the way to work. The total distance from his house to work is 23 miles. He walks at the rate of 4 m

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 5. An accountant walks part of the way and takes the bus the remaining part of the way to work. The total distance from his house to work is 23 miles. He walks at the rate of 4 m      Log On


   

Question 230816: 5. An accountant walks part of the way and takes the bus the remaining part of the way to work. The total distance from his house to work is 23 miles. He walks at the rate of 4 miles per hour while the bus travels at a speed of 35 miles per hour. The total trip time from his house to work is 2 hours. Calculate the distance the account travels by foot and the distance the accountant travels by bus
This is what I came up with so far:
Dw+Db=23
Dw/4 + Db/35=2
DW= Distance walked
DB=Distance bused
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
good so far...

w = 23 - b

substituting ___ ((23 - b) / 4) + (b / 35) = 2

multiplying by 140 (LCD) ___ 805 - 35b + 4b = 280

adding 31b-280 ___ 525 = 31b ___ 525/31 = b

substituting ___ w = 23 - 525/31