SOLUTION: A younger brother left his house on foot. Six minutes later his older brother followed him on a bicycle. If the younger brother is going 50 meters a minute and the older brother is
Question 223555: A younger brother left his house on foot. Six minutes later his older brother followed him on a bicycle. If the younger brother is going 50 meters a minute and the older brother is going 200 meters a minute, how many minutes will it take for the older brother to catch up to the younger brother? Can you please explain how to solve this problem using a linear equation? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A younger brother left his house on foot.
:
Six minutes later his older brother followed him on a bicycle.
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If the younger brother is going 50 meters a minute and the older brother is
going 200 meters a minute, how many minutes will it take for the older brother
to catch up to the younger brother?
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Can you please explain how to solve this problem using a linear equation
:
Let t = time for older brother to catch up
then
(t+6) = time for the younger brother to be caught (he started 6 min sooner)
:
When this happens they both will have traveled the same distance
write a distance equation: dist = speed * time
:
older's dist = younger's dist
200t = 50(t+6)
200t = 50t + 300
200t - 50t = 300
150t = 300
t =
t = 2 min
:
:
Check solution by finding the distance of each
200*2 = 400 m
50*(2+6) = 400 m
