SOLUTION: Soccer game. There were 1000 more students at the soccer game than nonstudents. Student tickets were $8.50 and nonstudent tickets were $13.25. If the total revenue for the game

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Question 159274This question is from textbook elementary & intermediate algebra
: Soccer game.
There were 1000 more students at the soccer game than nonstudents. Student tickets were $8.50 and nonstudent tickets were $13.25. If the total revenue for the game was $75,925, then how many tickets of each type were sold? This question is from textbook elementary & intermediate algebra

Found 2 solutions by jojo14344, nerdybill:
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Remember: Number of tickets
NonStudents=NS=x, no. of non students
Students=S=1000%2Bx, no. of students
Therefore,
%281000%2Bx%298.50%2B13.25%28x%29=75925 ----------------> working eqn
8500%2B8.50x%2B13.25x=75925
21.75x=75925-8500=67425
cross%2821.75%29x%2Fcross%2821.75%29=cross%2867425%293100%2Fcross%2821.75%29
x=3100 ------------------------------> no. of Nonstudents
1000%2B3100=4100 ----------------------> no. of Students
In doubt? go back working eqn:
%281000%2B3100%29%288.50%29%2B13.25%283100%29=75925
%284100%29%288.50%29%2B41075=75925
34850%2B41075=75925
75925=75925
Thank you,
Jojo

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
There were 1000 more students at the soccer game than nonstudents. Student tickets were $8.50 and nonstudent tickets were $13.25. If the total revenue for the game was $75,925, then how many tickets of each type were sold?
.
Let x = non-student tickets
then from "There were 1000 more students at the soccer game than nonstudents"
x+1000 = student tickets
.
And, because total revenue was $75,925:
13.25x + 8.50(x+1000) = 75925
13.25x + 8.50x + 8500 = 75925
21.75x + 8500 = 75925
21.75x = 67425
x = 3100 (non-student tickets)
.
student tickets:
x+1000 = 3100+1000 = 4100 (student tickets)