Question 142746: A Taxi driver takes R360 in fares per trip with a full load of passengers. If he increases his fare by R10 per passenger he can make the same amount where carrying three passengers less. What will the increased fare amount to, and how many passengers did he originally carry?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A Taxi driver takes R360 in fares per trip with a full load of passengers. If he increases his fare by R10 per passenger he can make the same amount where carrying three passengers less. What will the increased fare amount to, and how many passengers did he originally carry?
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Let original number carried be "x".
Average cost per person is 360/x
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New fare is (360/x) + 10 = (360+10x)/x per person
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EQUATION:
(3 less persons)*(fare per person) = 360
(x-3)[(360+10x)/x] = 360
(x-3)[(36+x)/x] = 36
(x-3)(36+x) = 36x
(x^2+33x-108) = 36x
x^2-3x-108= 0
x = [3 +- sqrt(3^2 -4*-108)]/2
x = [3 +- sqrt(441)]/2
x = [3 +- 21]/2
Positive solution:
x = 12 (original number of passengers)
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New fare: (360+10*12)/12 = R40
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Cheers,
Stan H.
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